Math, asked by silverstaks, 9 days ago

(1) 30° (2) 60° (3) 50° 4) 55 50. A Р B E C In the above AABC, AB|| DE, ZABC = 5 ZQPD. If ZDCP = 20° and QC is the bisector of ZACB, then 3 find ZBAC. (1) 20° (2) 40° (3) 60° (4) 80° 1.

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(1) 30° (2) 60° (3) 50° 4) 55 50. A Р B E C In the above AABC,

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(1) 30° (2) 60° (3) 50° 4) 55 50. A Р B E C In the above AABC, AB|| DE, ZABC = 5 ZQPD. If ZDCP = 20° and QC is the bisector of ZACB, then 3 find ZBAC. (1) 20° (2) 40° (3) 60° (4) 80° 1.​

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(1) 30° (2) 60° (3) 50° 4) 55 50. A Р B E C In the above AABC, AB|| DE, ZABC = 5 ZQPD. If ZDCP = 20° and QC is the bisector of ZACB, then 3 find ZBAC. (1) 20° (2) 40° (3) 60° (4) 80° 1.