(1/3a+2/3b)^3-(1/3a-2/3b)^3
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8
(1/3a+2/3b)^3-(1/3a-2/3b)^3
=1/27a^3+1/9a^2b+4/9ab^2+8/27b^3-(1/27a^3-1/9a^2b+4/9ab^2-8/27b^3)
=1/27a^3-1/27a^3+1/9a^2b+1/9a^2b+4/9ab^2-4/9ab^2+8/27b^3+8/27b^3
=2/9a^2b+16/27b^3
=1/27a^3+1/9a^2b+4/9ab^2+8/27b^3-(1/27a^3-1/9a^2b+4/9ab^2-8/27b^3)
=1/27a^3-1/27a^3+1/9a^2b+1/9a^2b+4/9ab^2-4/9ab^2+8/27b^3+8/27b^3
=2/9a^2b+16/27b^3
Answered by
3
this answer is = 4/9a²b +16/27 b³
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