Question

1+3i/1-2i in a+ib form​

Answer 1

here's your solution mate!

Answer 2

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$\frac{1 + 3i}{1 - 2i}$

now rationalise the denominator

$\frac{1 + 3i}{1 - 2i} \times \frac{1 + 2i}{1 + 2i}$

$= \frac{(1 + 3i)(1 + 2i)}{1 - 4i {}^{2} }$

$= \frac{1 + 2i + 3i + 6i {}^{2} }{1 - 4i {}^{2} }$

we know that

i² = -1

then,

_______________

$= \frac{1 + 5i - 6}{1 + 4}$

$= \frac{ - 5 + 5i}{5}$

$= - 1 + i$

I hope it helps you!