Question

1/3x^2-√11x+1=0. Find roots of d above eq. Plz give d process

Answer 1

Answer:

The root of the equation are 9.638 and 0.311.

Step-by-step explanation:

Given : Equation $\frac{1}{3}x^2-\sqrt{11}x+1=0$

To find : The roots of the equation ?

Solution :

$\frac{1}{3}x^2-\sqrt{11}x+1=0$ can be written as,

$x^2-3\sqrt{11}x+3=0$

Apply quadratic formula of equation $ax^2+bx+c=0$ is

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Here, a=1, $b=-3\sqrt{11}$ and c=3

Substitute the value,

$x=\frac{-(-3\sqrt{11})\pm\sqrt{(-3\sqrt{11})^2-4(1)(3)}}{2(1)}$

$x=\frac{3\sqrt{11}\pm\sqrt{99-12}}{2}$

$x=\frac{3\sqrt{11}\pm\sqrt{87}}{2}$

$x=\frac{3\sqrt{11}+\sqrt{87}}{2},\frac{3\sqrt{11}-\sqrt{87}}{2}$

$x=9.638,0.311$

Therefore, The root of the equation are 9.638 and 0.311.

Answer 2

Answer:

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