Math, asked by rounak07, 1 year ago

1/(3x+2y)+1/(3x-y)=3/4,1/2(3x+y)-1/2(3x-y)=-1/8

Answers

Answered by Anonymous
54
here x=1,y=1.........
Attachments:
Answered by Anonymous
41
putting the value of 1/3x+2y=u

and 1/3x-y=v
then,,
u+v=3/4☺☺☺☺☺☺☺☺
u/2 - v/2=-1/8
by elimination method,,
we get,
u+v=3/8
u/2-v/2=-1/8
___________
u=3/8 - 1/8
u=2/8=1/4
u=1/4
put the value of u in another equation,

u+v=3/4
1/4+v=3/4
v=3/4-1/4
v=1/2
v=1/2
put the value of u and v
1 /3x+y=1/4
3x+y=4 ------ (4)

1/3x-4=1/2
3x-y=2 ------( 5)
by elimination method to solving 4 and 5
3x+y=4
3x-y=2
_______
2y=2
y=2/2
y=1

put the value of y in another equation,,
3x+y=4
3x+1=4
3x=3
x=3/3
x=1


rounak07: ya
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