1/3x+y=10/3;2x+1/4y=11/4
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1x/3 + y = 10 .............(1)
Taking the LCM of the denominators and then solving it.
⇒ x + 3y = 30 ...........(2)
2x + 1y/4 = 11/4 .........(3)
Taking the LCM of the denominators and the solving it.
⇒ 8x + y = 11 ............(4)
Multiplying the equation (4) by 3, we get
⇒ (8x + y = 11)*3
= 24x + 3y = 33
Now subtracting it from equation (2)
x + 3y = 30
24x + 3y = 33
- - -
_______________
- 23x = - 3
_______________
⇒ 23x = 3
x = 3/23
Now, substituting the value of x = 3/23 in (2).
⇒ x + 3y = 30
⇒ 3/23 + 3y = 30
⇒ 3y = 30 - 3/23
⇒ 3y = (690 - 3)/23
⇒ 3y = 687/23
⇒ y = 687/23*3
⇒ y = 687/69
⇒ y = 229/23
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