Question

1÷3x+y=10÷3;2x+1÷4y=11÷4

Answer 1

Solution :-

1x/3 + y = 10 .............(1)

Taking the LCM of the denominators and then solving it.

⇒ x + 3y = 30 ...........(2)

2x + 1y/4 = 11/4 .........(3)

Taking the LCM of the denominators and the solving it.

⇒ 8x + y = 11 ............(4)

Multiplying the equation (4) by 3, we get

⇒ (8x + y = 11)*3

= 24x + 3y = 33 

Now subtracting it from equation (2) 

     x  + 3y = 30

  24x + 3y = 33

 -       -        -        

_______________

  - 23x    = - 3

_______________

⇒ 23x = 3

x = 3/23

Now, substituting the value of x = 3/23 in (2).

 ⇒ x + 3y = 30

⇒ 3/23 + 3y = 30

⇒ 3y = 30 - 3/23

⇒ 3y = (690 - 3)/23

⇒ 3y = 687/23

⇒ y = 687/23*3

⇒ y = 687/69

⇒ y = 229/23

Answer is 13.