Math, asked by dakhra, 1 year ago

(1-3y) (4-y)/ (2 -3y) ( 1-y) = 1

Answers

Answered by sonalmishra
38
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Answered by Ompanda
16
(1-3y)(4-y)/(2-3y)(1-y)=1
1(4-y)-3y(4-y)/2(1-y)-3y(1-y)=1
4-y-12y+3y²/2-2y-3y+3y²=1
3y²-13y+4/2-5y+3y²=1
3y²-13y+4-2+5y-3y²=1
3y²-3y²-13y+5y+4-2=4
-8y+2=4
-8y=4-2
-8y=-2
y=-2/-8
y=1/4

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