Question

(1) 3y2 + ky + 12 = 0​

Answer 1

ky = -12-3y2
K = -12-3y2 /y

Answer 2

Answer:

k = 12

Step-by-step explanation:

p(x) = 3y^2 +ky +12 = 0

a=3

b=k

c=12

it is given that the root of p(X) are equation and real

so,

b^2 - 4ac =0

k^2 - 4(3) (12) =0

k^2 = 144

k = 12

hope it help you