Question

(1/4^-2)-(1/3^-3)÷(2/1)^3​

Answer 1

{(1/4)-²}-{(1/3-³)}/(2)³

(4)²-(3)³/(2)³

16-9/4=64-9/4=55/4

Answer 2

Solution

$\implies( {\frac{1}{4} }^{ - 2} ) - ( { \frac{1}{3} }^{ - 3} ) \div {( \frac{2}{1} )}^{3}$

$\implies(16) - (27) \div (8)$

$\implies - 11 \div 8$

$\implies - 1.375$

Hope it helps you...