Question

1+4=4 ;2+5=12;3+6=21;9+12=?​

Answer 1

Answer:

So...the problem here is there is are MULTIPLE CORRECT ANSWERS, since the construct for this problem is not defined. Here are 5 perfectly valid ways to solve this with 5 different results. THERE ARE MORE VALID EQUATIONS that can solve this…this was just the first 5 I came up with.

(For those that are saying the addition is wrong and 8 + 5 is always 13, see my last two examples where the cross symbol is still a plus sign, and the answers still work with basic standard addition. Also, a cross symbol can also be used as a generic function symbol in some contexts. Dont be so closed minded.)

1 + 4 = 5

2 + 5 = 12

3 + 6 = 21

5 + 8 = ?

1 + 4 = 5

2 + 5 = 2 + 2(5) = 12

3 + 6 = 3 + 3(6) = 21

5 + 8 = 5 + 5(8) = 45

ALGORITHM: A + A(B) = C

ANSWER = 45

1 + 4 = 1 + 4 + (0) = 5

2 + 5 = 2 + 5 + (5) = 12

3 + 6 = 3 + 6 + (12) = 21

5 + 8 = 5 + 8 + (21) = 34

ALGORITHM: A + B + C' = C, where C' is the previous answer

ANS = 34

1 + 4 = 5 = 5

2 + 5 = (5 + 2) + (5) = 12

3 + 6 = (7 + 2) + (12) = 21

5 + 8 = (9 + 2) + (21) = 32

ALGORITHM: for {X=5, C = X + C' , X = X+2 };, where C' is the previous answer. A and B not used in equation,

ANS = 32

1 + 4 = 5

2 + 5 = 7 (base 5) =12

3 + 6 = 9 (base 4) = 21

5 + 8 = 13 (base 3) = 111

ALGORITHM: for {X=6, C = (A + B)^(10 -> X), X -1} (First answer in Base6, then Base 5, then 4, etc...)

ANS = 111

1 + 4 = 5

2 + 5 = 7 (base 5) =12

3 + 6 = 9 (base 4) = 21

4 + 7 = 11 (base 3) = 102

5 + 8 = 13 (base 2) (aka binary) = 1101

ALGORITHM: for {X=6, C = (A + B)^(10 -> X), X -1} (First answer in Base6, then

Base 5, then 4, etc...including "missing" numbers

ANS = 1101

Answer 2

Answer:

5+8 = 45

Step-by-step explanation:

its very simple bro :-)

1+4 = 1×4+1 = 4+1 = 5

2+5 = 2×5+2 = 10+2 = 12

3+6 = 3×6+3 = 18+3 = 21

4+7 = 4×7+4 = 28+4 = 32

Now,

5+8 = 5×8+ 5 = 40+5 = 45

(mark as brainliest if helped)