Question

plzz answer me .iwill definitely maek as brainlist.. and don't do rubbish thing​

Answer 1

Step-by-step explanation:

In △BOC,

∠OBC=∠OCB ----- (Opposite angle of isosceles triangle)

∠OBC+∠OCB+∠BOC=180

∘

25

∘

+25

∘

+∠BOC=180

∘

Therefore, ∠BOC=130

∘

So, ∠AOB+∠BOC=180

∘

--------(Linear pair)

∠AOB=180

∘

−130

∘

∠AOB=50

∘

So, the acute angle between the diagonal is 50

∘

.

Answer 2

Answer:

50

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