1+4=5 2+5=12 3+6=21 8+11=?
schandani:
1*4=4+1=5,.........2*5=10+2.......
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Solution :-
1+4 = 5 ; 2+5 = 12 ; 3+6 = 21 ; 8+11 = ?
If we see the series then we will find that the numbers in the series are in this way.
# (1*4) + 1 = 5
4 + 1 = 5
# (2*5) + 2 = 12
10 + 2 = 12
# (3*6) + 3 = 21
18 + 3 = 21
# (4*7) + 4 = 32 [Which is not given in the series]
28 + 4 = 32
# (5*8) + 5 = 45 [Which is also not given in the series]
40 + 5 = 45
# (6*9) + 6 = 60 [Which is also not given in the series]
54 + 6 = 60
# (7*10) + 7 = 77 [Which is also not given in the series]
70 + 7 = 77
# (8*11) + 8 = 96 [Number about which the question is asked]
88 + 8 = 96
So, the required number in the series will be 96.
Thanks for asking the question.
1+4 = 5 ; 2+5 = 12 ; 3+6 = 21 ; 8+11 = ?
If we see the series then we will find that the numbers in the series are in this way.
# (1*4) + 1 = 5
4 + 1 = 5
# (2*5) + 2 = 12
10 + 2 = 12
# (3*6) + 3 = 21
18 + 3 = 21
# (4*7) + 4 = 32 [Which is not given in the series]
28 + 4 = 32
# (5*8) + 5 = 45 [Which is also not given in the series]
40 + 5 = 45
# (6*9) + 6 = 60 [Which is also not given in the series]
54 + 6 = 60
# (7*10) + 7 = 77 [Which is also not given in the series]
70 + 7 = 77
# (8*11) + 8 = 96 [Number about which the question is asked]
88 + 8 = 96
So, the required number in the series will be 96.
Thanks for asking the question.
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