Question

1 4 7 - एक अंक सही है परन्तु उसकी जगह गलत है।
189 - एक अंक सही है और उसकी जगह भी सही है।
964 - दो अंक सही है, परन्तु उसकी जगह गलत है।
523 - सभी अंक गलत है।
286 - एक अंक सही है और उसकी जगह सही *नही है।​

Answer 1

AnswEr :

☯ Digit Can Be : 1, 2, 3, 4, 5, 6, 7, 8, 9.

From 1st Statement and 2nd we will Cancel Digit Number 1, Because it's Contradictory.

From Statement 4th we got that Code Digits can't be 5, 2 or 3.

☯ So Options Left : 4, 6, 7, 8, 9

From 2nd Statement and 5th Statement we will Cancel Digit Number 8, Because it's Contradictory.

From 2nd Statement we cancel all other two numbers i.e. 1 and, 8. So Left Number 9 is Correct and at Right Place.

⠀⠀⠀⠀⠀___⠀___⠀ 9

☯ Options Left : 4, 6, 7

From 6th Statement, we cancelled 2 and 8 already, therefore 6 will be another Digit of Code, but at wrong place.

From Statement 3rd we can see that Two Digits are Correct (9, 6) but at wrong place. So Digit 4 will be Eliminated and 6 will be at First Place of Code.

We will have left only one Digit that is 7 and will be at Middle Place of Code.

⋆ CODE : 6 ⠀ 7 ⠀ 9

Answer 2

Answer:

In First 2 statements, one digit is right. That means the No. 1 can’t be the code cuz it contradicts.

Then, at 4th statement, 5 2 3 are wrong numbers. Afterward, on 5th statement, eliminate the number 2, by compare it to the 2nd statement.

There, we conclude that the number 8 is also a wrong number, since if it iss right, then the 2nd statement will be false.

Therefore, number “9” is the first of the three numbers and is in the right place. The second number would be “6” since we would’ve eliminated “2” and “8” from statement 5.

By 3rd Statement we know 9 and 6 are part of the two right numbers, we can eliminate number 4.

Lastly, by 1st statement, which conclude number “7” as the right number. However, two of the numbers, 7 and 6, are still in the wrong place.

So, if 7 is in the wrong place from the first statement, and 6 is also in the wrong place from the third placement.

• CODE : 6 7 9