(1/4 a ^ 2 + 3b)(a ^ 3 + 2/3 b ^ 2)
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Here's your answer
Step-by-step explanation:
We have,
=[43a2+3b2]×[4(a2−32b2)]
=[43a2+3b2]×[4a2−38b2]
=412a4−1224a2b2+12a2b2−324b4
=3a4−2a2b2+12a2b2−8b4
=3a4+10a2b2−8b4
Hope you understand.
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