Question

If p(x) = 3−2+2, find p(0), p(1) and p(2). What do you conclude?

Answer 1

Answer:

p(x)=x^3-3x^2+2x

p(0) =0^3-3×0^2+2×0

=0-0+0

=0

p(1)=1^3-3×1^2+2×1

=1-3×1+2

=1-3+2

=3-3

=0

p(2)=2^3-3×2^2+2×2

=8-12+4

=12-12

Step-by-step explanation:

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