1/4 of the tank is contained fuel .when 11 litres if fuel is poured inti the tank the indicator rest at 1/2 mark . find the capacity
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Let capacity of the tank is x .
according to question, 1/4 of the tank is contained fuel.
e.g., amount of fuel in the tank = x/4
now 11 litre fuel is poured into the tank the indicator rest at 1/2 mark.
e.g., x/4 + 11 = x/2
=> x/4 + 11 = x/2
=> 11 = x/2 - x/4 = x/4
=> x = 11 × 4 = 44 litres
hence, capacity of the tank is 44 litres.
according to question, 1/4 of the tank is contained fuel.
e.g., amount of fuel in the tank = x/4
now 11 litre fuel is poured into the tank the indicator rest at 1/2 mark.
e.g., x/4 + 11 = x/2
=> x/4 + 11 = x/2
=> 11 = x/2 - x/4 = x/4
=> x = 11 × 4 = 44 litres
hence, capacity of the tank is 44 litres.
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