Question

1÷4×sin(300)+√(3÷8×tan(585)−√(3÷4×cos(390)

Answer 1

Answer:

[-sqrt(3)+sqrt(6)]/4

Step-by-step explanation:

1/4(sin(5pi/3))+√(3÷8×tan(5pi/4)-√(3÷4×cos(pi/6) I've just converted the values to radians so it's easier for me to solve

1/4(sqrt(3)/2)+sqrt(3/8*1)-sqrt(3/4*sqrt(3)/2), Simplify

sqrt(3)/8+sqrt(3)/2sqrt(2)-3sqrt(3)/8, simplify;

-2sqrt(3)/8+sqrt(3)/2sqrt(2); rationalize the denominator of the second term by multiplying the term by sqrt(2)/sqrt(2)

-2sqrt(3)/8+sqrt(6)/4, make the denominators the same;

-sqrt(3)/4+sqrt(6)/4, simplify;

[-sqrt(3)+sqrt(6)]/4