Question

1/4 Sin4A× SecA= SinA×Cos2A

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

$\frac{1}{4} sin4aseca \\ \\ = \frac{1}{4} 2sin2acos2a \times \frac{1}{cosa} \\ \\ = \frac{sin2acos2a}{2cosa} \\ \\ = \frac{2sinacosa \: cos2a}{2cosa} \\ \\ = sinacos2a$