Question

1.44 gram of Titanium reacted with excess of O2 and produce X gram of non stoichiometric compound TiO1.44 the value of x is

Answer 1

The chemical eqn. for the above problem is:Ti + 22O2 -----------> Ti1.44O.Now just simply apply mole analyisis-1 for Ti and x gram that product.like moles of Ti = 1.44/48 is the moles of Ti1.44O.

Answer 2

Hello dear!!! ✌️✌️


Here is your answer goes like this :
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1.77g. Firstly write the equation i.e Ti+O2--->Ti1.44O
Now using moles =given weight /molecularweight calculate moles and then relate moles formed in product and reactant,moles in reactant=1.44/48 and moles of Ti in product=1.44x/1.44*48+16
Therefore the X value is 1.77g



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