Question

(-√-1)^4ñ+3
Where n is a positive integer

Answer 1

Step-by-step explanation:

( - √-1^4n+3)

=(-i^4n+3). [a^{b+c}=a^b×a^c]

=(i^4n)(-i^3).

=(i)(-i). [i to the power 4n ] [i^3=-i]

=-i^2

=-(-1)

=1

Answer 2

Step-by-step explanation:

${ - \sqrt{ - 1} }^{4n + 3 } \\ \sqrt{ - 1 } = i \\ { - i}^{4n + 3 } = { - i}^{4n} + { - i}^{3} \\ { - i}^{4n} + - i$

1 + -i