Question

1. 5у - у+1/3 = 6y+1/5​

Answer 1

$\mathtt{5y-\Large\frac{y+1}{3} \normalsize = \Large\frac{6y+1}{5}}$

$\implies\mathtt{\Large\frac{15y-(y+1)}{3} \normalsize = \Large\frac{6y+1}{5}}$

$\implies \mathtt{\Large\frac{15y-y-1}{3} \normalsize = \Large\frac{6y+1}{5}}$

$\implies \mathtt{\Large\frac{14y-1}{3} \normalsize = \Large\frac{6y+1}{5}}$

$\mathtt{5(14y-1) = 3(6y+1)}$

$\mathtt{70y-5 = 18y+3}$

$\mathtt{70y-18y = 5+3}$

$\mathtt{52y = 8}$

$\mathtt{y = \Large\frac{8\!\!\!/}{52\!\!\!\!\!/}}$

$\mathtt{y = \Large\frac{2}{13}}$