Question

1/√5-√2-√7 rationlaise the denominator

Answer 1

[1/(√5-√2)-√7]*[(√5-√2)+√7/(√5-√2)+√7]

(√5-√2)+√7/(√5-√2)^-(√7)^

√5-√2+√7/5-2√10+2-7

√5-√2+√7/-2√10

√2-√5-√7/2√10

Again by rationalisation,

√2-√5-√7/2√10*2√10/2√10

(√2-√5-√7)2√10/40

(√2-√5-√7)√10/20

√2.√10-√5.√10-√7.√10/20

2√5-5√2-√70/20

Hope it helps !!!!!