1/√5+√3 + 1/√5-√3 rationalise the denominator
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Multiply the both the denominators. Then it will get rationalized.
1/ √5+√3 + 1/ √5 -√3 = √5-√3 +√5+√3/ 2 (because when √5+√3 multiplied with the other becomes the form of a^2 - b^2)
= 2√5/2 =√5
1/ √5+√3 + 1/ √5 -√3 = √5-√3 +√5+√3/ 2 (because when √5+√3 multiplied with the other becomes the form of a^2 - b^2)
= 2√5/2 =√5
Anonymous:
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now root 5× root 5 =5
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answers hope this help you 1/root5 +1/2 also 1/root5+16
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