1
х
5
(3x+4y)
(2x-3y)
+
(3
(1) A two digit number and the number with digits interchanged add up to
143. In the given number the digit in unit's place is 3 more than the
y ху
1
1
1
(5)
2(3x + 4y) 5(2x - 3y) 4
7. Solve the following word problems.
digit in the ten's place. Find the original number.
Let the digit in unit's place is x
and that in the ten's place is y
... the number =
y + x
+ x
x + y
The number obtained by interchanging the digits is
According to first condition two digit number + the number obtained by
interchanging the digits
= 143
10y + x
+
= 143
x +
y = 143
x + y =
..... (1)
From the second condition,
digit in unit's place = digit in the ten's place + 3
x =
+ 3
.. x - y = 3 . . . . . (II)
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