1.5
A body of mass 2 Kg is allowed to fall freely
from the top of a 50 m high tower. After one
second of its journey, its kinetic energy is-
[g=10m/s)
a) 100 J
b) 200 J
c) 50 J
d) 75 J
Answers
Answered by
1
Answer:
a) 100 J
Explanation:
When ball is at rest it will only have Potential Energy that is,
P.E=mgh
m= 2 kg;h=5 m
P.E=2×10×5=100J
This is the total energy as K.E is zero when the ball is at maximum height that is when it is at 5 m. Hence when the ball reaches the ground P.E becomes zero because of zero height.At this point,the total energy is equal to the K.E that is K.E=100J.
Answered by
0
a) 100J
m= 2kg, t= 1 sec, h= 50m, a= 10m/s, v= ?, KE= ?
We know that,
a= v/t => v= at
v= 10m/s^2 x 1 sec = 10m/s
Now, KE = 1/2 x m x v^2
KE= 1/2 x 2 x 10 x 10 J
KE= 100J
m= 2kg, t= 1 sec, h= 50m, a= 10m/s, v= ?, KE= ?
We know that,
a= v/t => v= at
v= 10m/s^2 x 1 sec = 10m/s
Now, KE = 1/2 x m x v^2
KE= 1/2 x 2 x 10 x 10 J
KE= 100J
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