1.5 A cubic solid is made up of two elements P and Q.
Atoms Q are present at the corners of the cube and
atom P at the body centre. What is the formula of the
compound?
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Answer:
Explanation:
As atoms of Q are present at the 8 corners of the cube.Number of atoms of Q in the unit cell =18×8=1
As atoms P are present at the body centre,therefore number of atoms of P in the unit cell =1
∴ Ratio of atoms = P : Q=1 : 1
Hence,the formula of the compound is PQ.Atoms at the body-centre would be in contact with all the atoms at the corners.Hence,the coordination number of P would 8,similarly,coordination number of Q is also 8.
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