Question

1.5 ग्राम NaOH युक्त 250 मिली विलयन की
मोलरता क्या होगी? (What will be the molarity
of a solution containing 5 gm NaOH in 250
ml solution ?):
(a) 0.1 M (b) 0.5 M (c) 1.0 M (d) 2M​

Answer 1

Answer:

the answer is this......opt b

Explanation:M=WT/GWTx1000/v(in ml)

                         =5/40x1000/250

                           =0.5mol/lit

Answer 2

The molarity of a solution containing 5 gm NaOH in 250 ml solution is 0.5M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n= moles of solute  

$V_s$ = volume of solution in ml = 250 ml

$moles of solute =\frac{\text {given mass}}{\text {molar mass}}=\frac{5g}{40g/mol}=0.125moles$

Now put all the given values in the formula of molarity, we get

$Molarity=\frac{0.125moles\times 1000}{250ml}$

$Molarity=0.5moles/L$

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