Question

1-522. A closed system undergoes a change of stateprocess 1- 2 for which Q12 = 10 J and W, = -51.The system is now returned to its initial state by adifferent path 2 + 1 for which Q21 is -3 J. The workdone by the gas in the process 2 →lis(a) 8J (b) zero (c) -23 (d) +5 J​

Answer 1

Answer:

Work done in the process 2 to 1 is given as 58 J

Explanation:

As we know that for a closed process

Net heat given = Net work done

so we have

$Q_{12} + Q_{21} = W_{12} + W_{21}$

now we have

$Q_{12} = 10 J$

$W_{12} = -51 J$

$Q_{21} = -3 J$

so we have

$10 - 3 = -51 + W_{21}$

$7 + 51 = W_{21}$

$W_{21} = 58 J$

#Learn

Topic : First Law of thermodynamics

https://brainly.in/question/12187490