Question

The z-score associated with 98% is 2.33. if the sample p-hat is 0.60 and the standard deviation is 0.02, find the lower limit of the 98% confidence interval."

Answer 1

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Answer 2

The lower limit of the 98% confidence interval is 0.55.

Step-by-step explanation:

Given:

z₀.₀₁ = 2.33

$\hat p$ = 0.60

SD = 0.02

Solution:

The lower limit of the 98% confidence interval for population proportion is:

$LL=\hat p-z_{0.01}\times SD\\=0.60-(2.33\times 0.02)\\=0.5534\\\approx0.55$

Thus, the lower limit of the 98% confidence interval is 0.55.