Question

1. 6 men and 10 women can finish making pots in 8 days, while the 4 men and 6 women can finish it in 12 days. Find the time taken by the one man alone from that of one woman alone to finish the work.

Answer 1

Answer:

let time taken by men be x days

time taken by women be y days

then,

in one day a man completes 1/x

in one day a woman completes 1/y

6/x +10/y =1/8

and

4/x+6/y= 1/12

let 1/x =a

1/y=b

then 6a + 10b = 1/8 -(1)

4a + 6b = 1/12 -(2)

(1)*4=> 24 a+ 40b = 1/32-(3)

(2)*6=> 24a +36b = 1/76 -(4)

(3)-(4) and substitute

Answer 2

Answer:

let time taken by men be y days

let time taken by women be x days

then,

in one day a man completes 1/y

in one day a woman completes 1/x

6/y +10/x =1/8

and

4/y+6/x= 1/12

let 1/y =b

1/x=ba

then 6b + 10a = 1/8 -(1)

4b + 6a = 1/12 -(2)

(1)*4=> 24a + 40b = 1/32 - (3)

(2)*6=> 24a + 36b = 1/76 - (4)