Question

1. 64 g of copper reacts with 16 g of oxygen to give the black compound copper (II) oxide.
X = mass of copper Y = mass of oxygen

a. What mass of copper will react with 32 g of oxygen?
Ans – 64/64+16 *100 = 0.8*100 = 80%
x/x+32 * 100 = 80
->100x = 80x+ 2560
-> x = 128

b. What mass of oxygen will react with 32 g of copper?
32/32+x * 100 = 80
Cross multiply
3200=2560 + x
X/mass of copper= 640g

c. What mass of copper (II) oxide will be formed, in b?
(whats the ans of c?)

Answer 1

Answer:

100x = 80x+ 2560

-> x = 128

b. What mass of oxygen will react with 32 g of copper?

32/32+x * 100 = 80

Cross multiply

3200=2560 + x

X/mass of copper= 640g

c. What mass of copper (II) oxide will be formed, in b?

(whats the ans of

Explanation:

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