Question

1-64a³-12a+48a², Factorise it.

Answer 1

Rearranging. =64a^3+48a^2-12a. Dividing equation by 4a,. =16a^2+12a-3 =( 16a^2+12a) -3. =4a(4a+3)-3.

Answer 2

Answer:

-(4a-1)³

Step-by-step explanation:

We have to factorize the algebraic expression 1-64a³-12a+48a².

Now, taking -1 as common from each term of the expression we get,

1-64a³-12a+48a²

= -(64a³-48a²+12a-1)

Now, we can express 64a³ as (4a)³ and similarly 48a²=3×(4a)²×1 and 12a=3×(4a)×1² and finally 1=1³. Hence, the expression becomes

= -[(4a)³-3×(4a)²×1+3×(4a)×1²-1³]

=-(4a-1)³ {As we know the formula (x-y)³=x³-3x²y+3xy²-y³}

Hence, this is the required factorization of the given expression. (Answer)