An electric iron of resistance 30 ohms takes current of 15 amphear calculate the heat produced in 40 sec
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Answered by
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r=30 ohm
i=15 A
t=40 sec
Now,
H=15×15×30×40
H=270000 J
So the heat produced is 270 KJ
Answered by
0
H = I^2rt
r=30 ohm
i=15 A
t=40 second
H=15×15×30×40
H=270000 J
therefore , the heat produced is 270000J
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