Question

1/7,2/7,3/7.....are the sequence.What is the sum of sum of the first 7 terms of this sequence?

Answer 1

Answer: Sum of the first 7 terms = 4

Step-by-step explanation:

The AP is 1/7, 2/7, 3/7............

   common difference = $t_{2} - t_{1}$

                                     = 2/7 - 1/7

                                     = 1/7

Therefore, a= 1/7, d= 1/7

Using sum of 'n' terms formula,

$S_{n} = n/2 [2a + (n-1)d]$

$S_{7}$ = 7/2 [2*1/7 + (7-1)* 1/7]

$S_{7}$ = 7/2 [2/7 + (6)* 1/7]

$S_{7}$ = 7/2 [2/7 + 6/7]

$S_{7}$ = 7/2 [8/7]

$S_{7}$ = 56/14

$S_{7}$ = 4

Therefore sum of the first 7 terms of the sequence is 4

Answer 2

Answer:

9/9

Step-by-step explanation:

5/9+/

2/9+4/9=9/9

5+2+4=9

9 9 9 9