Question

1) 7,9,11
2) 6,9, 12
1, 10, 11
4. If the sum of three numbers which are in A.P is 15 and the sum of the squares of the
extremes is 58, then those numbers are
1) 3,5,7
2) 2, 5,8
3) 3, 6, 9
4) None​

Answer 1

Answer:

3,5,7

Step-by-step explanation:

Let the three numbers in A.P. be a−d,a,a+d Sum=3a=15

a=5 Sum of their squares=(a−d)^2+a^2+(a+d) ^2=83

3a ^2 +2d ^2 =83

2d ^2 =83−3×25

d ^2=4 or d=±2

Hence the numbers are 3,5,7

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