Question

1/7(x-9)+x/3=3 . solve for x​

Answer 1

Given :

$\\ \red \bullet \bf \: \frac{1}{7}(x - 9) + \frac{x}{3} = 3$

To Find :

• The value of x =?

Solution :

$\\ \implies \bf \: \frac{1}{7} (x - 9) + \frac{x}{3} = 3$

$\\ \implies \sf \: \frac{(x - 9)}{7} + \frac{x}{3} = 3$

$\\ \implies \sf \: \frac{3(x -9) + 7x}{21} = 3$

$\\ \implies \sf \: \frac{3x - 27 + 7x}{21} = 3$

$\\ \implies \sf \: 10x - 27 = 63$

$\implies \sf \: 10x - 27 - 63 = 0$

$\implies \sf \: 10x - 90 = 0$

$\\ \implies \sf \: x = \cancel \frac{90}{10}$

$\implies \boxed{ \bf{x = 9}}$

The answer will be $\boxed{\bf{x=9}}$

Answer 2

Answer:

$\frac{1}{7} (x - 9) + \frac{x}{3} = 3 \\ \frac{3(x - 9) + 7x }{21} = 3 \\ \frac{3x - 27 + 7x}{21} = 3 \\ \frac{10x - 27}{21} = 3 \\ 10x - 27 = 63 \\ 10x = 63 + 27 \\ 10x = 90 \\ x = \frac{90}{10} \\ x = 9$

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