Math, asked by rishika5379, 9 months ago

1
71. Sayali had some chocolates. She gave -1/3 rd of it to Aryan,
of it to Aryan, 1/6-th to Gargi and 1/12th
to Ayush. 10 chocolates remained with her. How many chocolate did she gave
to Gargi
the answer is 4 but how pls solve my doubts ​

Answers

Answered by santy2
5

Answer:

Sayali had some chocolates. She gave -1/3 rd of it to Aryan,

of it to Aryan, 1/6-th to Gargi and 1/12th

to Ayush. 10 chocolates remained with her. She gave Gargi 4 chocolates.

Step-by-step explanation:

Let's write down the information below.

Aryan = 1/3

Gargi = 1/6

Ayush = 1/12

Let's add the fractions first.

1/3 + 1/6 + 1/12 = 7/12

The remaining amount of chocolate is given by:

1 - 7/12 = 5/12

From the question, we have that 10 chocolates remained.

So, 5/12 = 10

The total number of chocolates is given as:

= 12/5 × 10 = 24 chocolates.

Gargi = 1/6 × 24 = 4 chocolates

So, Sayali gave Gargi 4 chocolates.

Similar questions