Question

(1)8^0×4^0÷8^0+4^0=​

Answer 1

We know that anything raised to 0 is 1

$i.e. \\ if \: x {}^{0} = 1 \\ or \\ (123456789) {}^{0} = 1$

thus

$\frac{ 8 {}^{0} \times 4 {}^{0} }{8 {}^{0} + 4 {}^{0} } \\ = \frac{1 \times 1}{1 + 1} \\ = \frac{1}{2}$