1/8 of a pole is in the mud, 1/3 is in water and the rest of 52 metres is above water.find the length of the pole.
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Answered by
28
let the full length of rope is x
then
1/8 of x is x/8
1/3 of rope is x/3
then
x/8 + x/3 +52= x
52=x-x/8 -x/3
52=(24x-3x-8x)/24
52*24=24x-11x
1248 = 13x
1248/13= x
96= x
then the full length of rope is 96metres
then
1/8 of x is x/8
1/3 of rope is x/3
then
x/8 + x/3 +52= x
52=x-x/8 -x/3
52=(24x-3x-8x)/24
52*24=24x-11x
1248 = 13x
1248/13= x
96= x
then the full length of rope is 96metres
Answered by
14
let height of pole = x metre
so, 1/8of x +1/3of x + 52m = x meter.
11x+1248 =24x
13x = 1248
x = 96m.
so, 1/8of x +1/3of x + 52m = x meter.
11x+1248 =24x
13x = 1248
x = 96m.
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