Question

1.84 gram mixture of CaCO3 and MgCO3 isl heated gave 0.96g. What is the % Mgco3 composition of mixture also gave chemical equation

Answer 1

$\bf{\huge{\underline{Question}}}$

1.84g mixture of CaCO3 and MgCO3 was heated to a constant weight to give 0.96g residue. What is the % Mgco3 composition of mixture also gave chemical equation.

$\bf{\huge{\underline{Answer}}}$

Let the mass of $CaCO_{3}$ be $x$g

So,the mass of $MgCO_{3}$ will be $(1.84 - x)$g

Now, $x$ g of $CaCO_{3}$ will give Cao $= \frac{56x}{100}$g

And, $(1.84 - x)$g of $MgCO_{3}$ will give MgO $= \frac{40(1.84-x)}{84}$g

Total mass of residue is 0.96g

So,$\frac{0.56+40(1.84-X)}{84}$ g= 0.96 g.

$x$=1g

Hence, % composition of $CaCO_{3}$ $= \frac{1}{1.84} \times 100 \\ =54.35\%$

And,% composition of $MgCO_{3}$ $=100\%-54.35\% \\ =45.65\%$

Answer 2

Answer:

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