Question

1/8a3 -1/27b3 factorisation​

Answer 1

Answer:

$\frac{1}{8} {a}^{3} - \frac{1}{27} {b}^{3} \\ {( \frac{1}{2}a) }^{3} - {( \frac{1}{3}b) }^{3} \\ = ( \frac{a}{2} - \frac{b}{3} )( ( { \frac{a}{2} )}^{2} + { (\frac{b}{3} )}^{2} + \frac{a}{2} \times \frac{b}{3} ) \\ = ( \frac{a}{2} - \frac{b}{3} )( \frac{ {a}^{2} }{4} + \frac{ {b}^{2} }{9} + \frac{ab}{6} )$