Math, asked by akshat12337, 8 months ago

1
9. 4. The perimeter of triangle is 13cm and its width is 2-3/4and find its length

Answers

Answered by minhaziyan
0

Answer:

The perimeter of a rectangle is 13 cm and its breadth is 2 3/4cm

let lenght be l

now   2 3/4

=> 11/4 cm

perimeter of rectangle = 2(l+b)

so ,

13 =  2(l+b)

13 =  2(l+11/4)

13 = 2l +11/2

13 - 11/2 = 2l

26-11/2 = 2l

15/2 = 2l

=>l= 15/2*2

=>l = 15/4cm  

hope it helps u

:)

Answered by s15958
0

Answer:

Let 'l' and 'b' the length and width of the rectangle respectively.

Given, b=2  \frac{3}{4} cm  =  \frac{11}{4} cm

perimeter of the rectangle = 13 cm

2(l + b) = 13

⇒ 2l + 2b = 13

⇒2l + 2(  \frac{11}{4}) = 13

⇒2l+  2 \frac{11}{2} =13

⇒2l = 13 − \frac{11}{2}  

​⇒2l=  \frac{26-11}{2}

​⇒ l =  \frac{15}{4} cm

∴ length of the rectangle =  \frac{15}{4} cm

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