what is the maximum possible value of the product of an integer and it's additive inverse?(a) 1 (b) 0 (c) -1 (d) None of these
Answers
Answer:
the answer will be 1......
n multiplication of integers, we use the following rules:
Rule 1
The product of two integers of opposite signs is equal to the additive inverse of the product of their absolute values.
Thus, to find the product of a positive and a negative integer, we find the product of their absolute values and assign minus sign to the product.
For example:
(i) 7 × (-6) = - (7 × 6) = -42
(ii) (-9) × 5 = - (9 × 5) = -45
(iii) 3 × (-9) = - (3 × 9) = -27
(iv) (-4) × 5 = - (4 × 5) = -20
HOPE IT WILL HELPFUL
Rule 2
The product of two integers with like signs is equal to the product of their absolute values.
(i) The product of two positive integers is positive.
In this, we take the product of the numerical values of the multiplier and multiplicand.
For example; (+ 7) × (+ 3) = + 21
(ii) The product of two negative integers is positive.
In this, we take the product of the numerical values of multiples and multiplicands and assign (+) sign to the product obtained.
For example: (- 7) × (- 3) = + 21
Thus to find the product of two integers, either both are positive or negative, we find the product of their absolute values.
For example:
(i) 7 × 11 = 77
(ii) (-9) × (-12) = 9 × 12 = 108
(iii) 5 × 12 = 60
(iv) (-9) × (-13) = 9 × 13 = 117