Math, asked by singhankushnarayan50, 8 months ago

what is the maximum possible value of the product of an integer and it's additive inverse?(a) 1 (b) 0 (c) -1 (d) None of these​

Answers

Answered by pratyushranjan69
3

Answer:

the answer will be 1......

Answered by BhardwajAtharv
0

n multiplication of integers, we use the following rules:

Rule 1

The product of two integers of opposite signs is equal to the additive inverse of the product of their absolute values.

Thus, to find the product of a positive and a negative integer, we find the product of their absolute values and assign minus sign to the product.

For example:

(i) 7 × (-6) = - (7 × 6) = -42

(ii) (-9) × 5 = - (9 × 5) = -45

(iii) 3 × (-9) = - (3 × 9) = -27

(iv) (-4) × 5 = - (4 × 5) = -20

HOPE IT WILL HELPFUL

Rule 2

The product of two integers with like signs is equal to the product of their absolute values.

(i) The product of two positive integers is positive.

In this, we take the product of the numerical values of the multiplier and multiplicand.

For example; (+ 7) × (+ 3) = + 21

(ii) The product of two negative integers is positive.

In this, we take the product of the numerical values of multiples and multiplicands and assign (+) sign to the product obtained.

For example: (- 7) × (- 3) = + 21

Thus to find the product of two integers, either both are positive or negative, we find the product of their absolute values.

For example:

(i) 7 × 11 = 77

(ii) (-9) × (-12) = 9 × 12 = 108

(iii) 5 × 12 = 60

(iv) (-9) × (-13) = 9 × 13 = 117

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