Question

1
9
If x
+
22
find the value of
of (
5x
25.12​

Answer 1

Step-by-step explanation:

${x}^{2} + \frac{1}{25 {x}^{2} } = 9 \frac{2}{5} \\ \\ \\ = >( x - \frac{1}{5x} ) ^{2} + \frac{2}{5} = (\frac{47}{5} )^{2} \\ \\ \\ = > (x - \frac{1}{5x} ) {}^{2} = \frac{2209}{25} - \frac{2}{5} \\ \\ \\ = > (x - \frac{1}{5x} ) {}^{2} = \frac{2209 - 10}{25} \\ \\ = > (x - \frac{1}{5x} ) {}^{2} = \frac{2199}{25} \\ \\ \\ = > (x - \frac{1}{5x} ) = \sqrt{ \frac{2199}{25} } \\ \\ \\ = > x - \frac{1}{5x} = \frac{ \sqrt{2199} }{5}$

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