Question

` 1,980 is divided among a, b and c so that half of a's part, one-third of b's part and one-sixth of c's part are equal. then b's part is

Answer 1

Answer:

a/2=b/3=c/6=k (say)

then;

a=2k,b=3k,c=6k

total=1980

2k+3k+6k=1980

11k=1980

k=180

b's part=3k

=3×180

=540

Answer 2

The b's part is 540.

Given:

1,980 is divided among a, b and c so that half of the a's part, one-third of b's part and one-sixth of c's part are equal.

To Find:

b's part.

Solution:

To find the b's part we will follow the following steps:

According to the question:

$\frac{a}{2} = \frac{b}{3} = \frac{c}{6}$

Let the ratio be equal to k.

So,

$\frac{a}{2} = \frac{b}{3} = \frac{c}{6} = k$

Now,

a = 2k, b = 3k, c = 6k

Also,

The sum of a, b and c is 1980.

So,

a + b + c = 1980

2k + 3k + 6k = 1980

11k = 1980

$k = \frac{1980}{11} = 180$

b's part = 3k = 3 × 180 = 540

Henceforth, the b's part is 540.

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