Math, asked by Anonymous, 3 months ago

1 . (993)³
2 . (1002)³

Evaluate the following products using "ALGEBRAIC IDENTITIES"​

Answers

Answered by tusharduhan2003
1

Answer:

write both of these in the form of (a +- b) ^3

Step-by-step explanation:

1) (1000-7)^3

2) (1000+2)^3

Answered by Anonymous
10

Answer:

1. 979146657

2. 1006012008

Step-by-step explanation:

1.

( 993 )³

( 993 )³= ( 1000 - 7 )³

( 993 )³

= ( 1000 - 7 )³

( a - b )³ = a³ - b³ - 3ab ( a - b ) { Identify }

where,

a = 1000

b = 7

= 1000³ - 7³ - 3 ( 1000 ) ( 7 ) [ 1000 - 7 ]

= 1000000000 - 343 - 21000 [ 1000 - 7 ]

= 1000000000 - 343 - 21000000 + 147000

= 1000000000 + 147000 - 343 - 21000000

= 1000147000 - 21000343

= 979146657

Therefore, ( 993 )³ = 979146657

2.

( 1002 )³

= ( 1000 + 2 )³

( a + b )³ = a³ + b³ + 3ab ( a + b ) { Identify }

where,

a = 1000

b = 2

= 1000³ + 2³ + 3 ( 1000 ) ( 2 ) [ 1000 + 2 ]

= 1000000000 + 8 + 6000 [ 1000 + 2 ]

= 1000000000 + 8 + 6000000 + 12000

= 1006012008

Therefore, ( 1002 )³ = 1006012008

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