1. A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.
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Explanation:
Percentage composition of boron=(mass of boron in sample/total mass of sample)=(0.096/0.24)×100=40%
Percentage composition of oxygen=(mass of oxygen in sample/total mass of sample)=(0.144/0.24)×100=60%
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