Question

1/a-1 +3/3a-1=0 please find the answer​

Answer 1

Step-by-step explanation:

$\frac{1}{a - 1} + \frac{3}{3a - 1} = 0 \\ \\ \frac{3a - 1 + 3(a - 1)}{(a - 1)(3a - 1)} \\ \\ \frac{3a - 1 + 3a - 3}{3 {a}^{2} - a - 3a + 1 } \\ \\ \frac{6a - 4}{3 {a}^{2} - 4a + 1 } \\ \\ \frac{2(3a - 2)}{3 {a}^{2} - 3a - a + 1 } \\ \\ \frac{2(3a - 2)}{3a(a - 1) - 1(a - 1)} \\ \\ \frac{2(3a - 2)}{(3a - 1)(a - 1)}$

2(3a-2)/(3a-1)(a-1) = 0

2(3a-2) = 0

3a-2 = 0

3a = 2

a = 2/3

Proof -

Putting a = 2/3 on 1/a-1 +3/3a-1=0

1/2/3-1 + 3/3×2/3-1 = 0

1/-1/3 + 3/1 = 0

3/-1 + 3/1 = 0

- 3 + 3 = 0

0 = 0

L•H•S = R•H•S