Math, asked by imransyedqatar, 1 year ago

1+a*a=17, A*b*b=36, A*b*c=72, a-b+c=?

Answers

Answered by alex57
0
1+a*a = 17
a*a = 17-1
a^2 = 16
a = 4

now
a*b*b = 36
4*b^2 = 36
b^2 = 36/5
b^2 = 9
b = 3

now we have
a*b*c = 72
4*3*c = 72
12*c = 72
c = 72/12
c = 6

so we get
a = 4
b = 3
c = 6

now we have to find
a - b + c
4 - 3 + 6
7

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